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October 13th, 2014

10/13/2014

4 Comments

 
The new idea today was that we could solve quadratic equations by manipulating the vertex form.

HW: Complete the Khan Academy Exercises below.
tt6_2.6_max_and_min_of_quadratic_13-10-2014.pdf
File Size: 267 kb
File Type: pdf
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KA Solve Quadratic by Completing the Square 1
KA Solve Quadratic by Completing the Square 2
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4 Comments
student
10/13/2014 12:57:15 pm

in the example how did you get ( -2.3) as an answer

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Mr R
10/13/2014 01:33:25 pm

It's how you read the vertex form to derive the max/min point. If the vertex form is say "m(x-p)^2 +q" then the vertex is (p, q). In other words the vertex's x-coordinate is found by changing the sign of the number after the x in the brackets, and the y-coordinate is equal to the constant term being added/subtracted outside the brackets. So the answer here is (-2, -3)

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/
10/13/2014 02:02:40 pm

thanks sir , still confused though :/

Mr R
10/13/2014 02:04:16 pm

Thanks for letting me know. Will go through it in class again tomorrow.

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