The new idea today was that we could solve quadratic equations by manipulating the vertex form. HW: Complete the Khan Academy Exercises below. 

4 Comments
student
10/13/2014 12:57:15 pm
in the example how did you get ( 2.3) as an answer
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Mr R
10/13/2014 01:33:25 pm
It's how you read the vertex form to derive the max/min point. If the vertex form is say "m(xp)^2 +q" then the vertex is (p, q). In other words the vertex's xcoordinate is found by changing the sign of the number after the x in the brackets, and the ycoordinate is equal to the constant term being added/subtracted outside the brackets. So the answer here is (2, 3)
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10/13/2014 02:02:40 pm
thanks sir , still confused though :/
Mr R
10/13/2014 02:04:16 pm
Thanks for letting me know. Will go through it in class again tomorrow.
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