SpatialMaths.com
  • Home
    • Junior Cycle Mock survey 2020
    • Spatial Quiz 2
  • Resources
  • About & Contact
    • Research

October 13th, 2014

10/13/2014

4 Comments

 
The new idea today was that we could solve quadratic equations by manipulating the vertex form.

HW: Complete the Khan Academy Exercises below.
tt6_2.6_max_and_min_of_quadratic_13-10-2014.pdf
File Size: 267 kb
File Type: pdf
Download File

KA Solve Quadratic by Completing the Square 1
KA Solve Quadratic by Completing the Square 2
Picture
4 Comments
student
10/13/2014 12:57:15 pm

in the example how did you get ( -2.3) as an answer

Reply
Mr R
10/13/2014 01:33:25 pm

It's how you read the vertex form to derive the max/min point. If the vertex form is say "m(x-p)^2 +q" then the vertex is (p, q). In other words the vertex's x-coordinate is found by changing the sign of the number after the x in the brackets, and the y-coordinate is equal to the constant term being added/subtracted outside the brackets. So the answer here is (-2, -3)

Reply
/
10/13/2014 02:02:40 pm

thanks sir , still confused though :/

Mr R
10/13/2014 02:04:16 pm

Thanks for letting me know. Will go through it in class again tomorrow.

Reply



Leave a Reply.

    Archives

    June 2015
    May 2015
    April 2015
    March 2015
    February 2015
    January 2015
    December 2014
    November 2014
    October 2014
    September 2014
    August 2014

    RSS Feed

    Author

    Mr Roche

    Categories

    All